C#随机生成18位身份证号码

Posted on | 一月 28, 2010 | No Comments

In fact, the PIN code is just simple, but only with a checksum in the last char. With many guys asp/php and also js s help, I get on my way!
private void GenPinCode()
  {

System.Random rnd;
  string[] _crabodistrict=new string[]{“350201″,”350202″,”350203″,”350204″,”350205″,”350206″,”350211″,”350205″,”350213″};
   rnd = new Random(System.DateTime.Now.Millisecond);
  
   //PIN = District + Year(50-92) + Month(01-12) + Date(01-30) + Seq(001-600)
   string _pinCode=string.Format(“{0}19{1}{2:00}{3:00}{4:000}”,_crabodistrict[rnd.Next(0,8)],rnd.Next(50,92),rnd.Next(1,12),rnd.Next(1,30),rnd.Next(1,600));
   #region Verify
   char[] _chrPinCode = _pinCode.ToCharArray();
   //校验码字符值
   char[] _chrVerify=new char[]{1, 0, X, 9, 8, 7, 6, 5, 4, 3, 2};
   //i—-表示号码字符从由至左包括校验码在内的位置序号；
   //ai—-表示第i位置上的号码字符值；
   //Wi—-示第i位置上的加权因子，其数值依据公式intWeight=2（n-1）(mod 11)计算得出。
   int[] _intWeight=new int[]{7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2, 1};
   int _craboWeight=0;
   for(int i=0;i<17;i++)//从1 到 17 位,18为要生成的验证码
   {
    _craboWeight=_craboWeight+Convert.ToUInt16(_chrPinCode[i].ToString())*_intWeight[i];
   }
   _craboWeight=_craboWeight%11;
   _pinCode+=_chrVerify[_craboWeight];
   #endregion
   this.txtPIN.Text=_pinCode;
  }

此文转载自http://blog.csdn.net/crabo/

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